Hasse-Minkowski

Local Global principle for quadratic forms over a field. Why is it true? How do the local solutions “force” Global solutions?

Let stick to rationals. What happens for n=2 variables? This case basically corresponds to understanding the form X^2-aY^2. Having a non-trivial rational solution corresponds to a being a square. And this can be checked locally! (Every non-square is not a square modulo some prime p-why?- even this fact is slightly tricky for other number fields)

What about n=3? Focus on aX^2+bY^2-Z^2. Here we need ideas about Hilbert symbol- (bilinear properties of Hilbert symbol corresponds to multiplicativity of norms on quadratic extensions- basically when you multiply expression of the form X^2-DY^2 we get another expression of the same form!) – this fact can be used to reduce from aX^2+bY^2-Z^2. to another form with smaller coefficients a, b. Keep doing this reduction and finally verify the local to Global principle for the few forms that you get at the end.

n=4 : aX^2+bY^2-cZ^2-dT^2. We can find $t_p$ non-zero mod p such that aX^2+bY^2=t_p,  cZ^2-dT^2=t_p because we have solutions mod p for aX^2+bY^2-cZ^2-dT^2=0. In general $t_p^k$ for all prime power $p^k.$ Construct a rational $t$ that locally looks like these $t_p^k.$- why does such a number exist? – (Apply Chinese Remainder theorem etc.) So we have aX^2+bY^2=t, cZ^2-dT^2=t locally. That is we have local solutions to aX^2+bY^2=tU^2, cZ^2-dT^2=tV^2. By using the above argument for $n=3$ we get rational solutions to aX^2+bY^2=tU^2, cZ^2-dT^2=tV^2. Scaling and subtracting t from these equations gives a non-trivial rational solution to our initial quadratic form. (some more work..)

n \ge 5: aX^2+bY^2+cZ^2+dT^2+eW^2-again split into two forms and reduce to smaller cases…

What is the source of getting global solutions from local solutions? 1. Being a square can be checked locally. 2. For n=3, we apply the reductions to solve equations with bigger coefficients by using equations with smaller coefficients. 3. What happens for n>4?

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