Jacobi Sums and Fermat’s theorem on Sums of Squares.

Look at the Gauss Sum

\displaystyle G(\chi) = \sum_{ x \mod p} \chi(x) e(\frac{2\pi ix}{p})

for a multiplicative character {\mod p.}

It’s easy to see by executing the double sum {G(\chi) \bar G(\chi)} (with a change of variables) that

\displaystyle |G(\chi)| =\sqrt{p},

(determining sign is more harder- you can apply poisson summation or Gauss’s {q}-binomial identities etc to determine the sign)

Consider the Jacobi Sums.

\displaystyle J(\chi, \psi) = \sum_{x \mod p} \chi(x) \psi(1-x)

Gauss Sums are the analogues of the Gamma function and Jacobi Sums are analogue of Beta function.

We have the following identity that relates Jacobi Sums to Gauss Sum- the analogue to the identity {B (a, b) =\frac{\Gamma(a) \Gamma(b)}{\Gamma(a+b)}}

\displaystyle J(\chi, \psi) =\frac{G(\chi)G(\psi)}{G(\chi\psi)}

provided {\chi\psi} is not a trivial character.

It is easy to see the above equality starting from {G(\chi) G(\psi)} which is a sum over {x_1, x_2 \mod p} and a change of variables { x_2 \rightarrow x_1t}

Fermat’s theorem: We want to prove that every prime {p \equiv 1 \mod 4} is a sum of squares, that is there are integers {a, b} such that {p =a^2+b^2.}

If {p \equiv 1 \mod 4}, then {4| |F_p^{*}|}
Hence there is an order 4 character {\chi \mod p.}

Look at

{\displaystyle J(\chi, \chi) = \sum_{x} \chi(x) \chi(1-x)},

which will a sum of numbers from {1, -1, i, -i}, because {\chi} takes values in the set of fourth roots of unity {\{\pm i, \pm i\}.}

Thus {J(\chi, \chi) =a+bi} for some integers {a, b.}

Let us look at {|J(\chi, \chi)|^2.} It equals

\displaystyle \frac{|G(\chi)|^2|G(\chi)|^2}{|G(\chi^2)|^2}

by the factorization of Jacobi Sums into Gauss Sums seen before.

Therefore

\displaystyle a^2+b^2=|J(\chi, \chi)|^2 =\frac{|G(\chi)|^2|G(\chi)|^2}{|G(\chi^2)|^2}= p.

We found a way to write {p} as a sum of squares!

Posted in $.

Leave a comment